- Split input into 2 regimes
if x < -0.0006290873782508793 or 0.0009486447256490275 < x
Initial program 0.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied add-sqr-sqrt0.8
\[\leadsto \color{blue}{\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}} - 1\]
- Using strategy
rm Applied add-cbrt-cube0.0
\[\leadsto \color{blue}{\sqrt[3]{\left(\left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right) \cdot \left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right)\right) \cdot \left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right)}} - 1\]
if -0.0006290873782508793 < x < 0.0009486447256490275
Initial program 59.1
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied add-sqr-sqrt59.1
\[\leadsto \color{blue}{\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}} - 1\]
- Using strategy
rm Applied add-cbrt-cube59.1
\[\leadsto \color{blue}{\sqrt[3]{\left(\left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right) \cdot \left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right)\right) \cdot \left(\sqrt{\frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt{\frac{2}{1 + e^{-2 \cdot x}}}\right)}} - 1\]
Taylor expanded around 0 60.2
\[\leadsto \color{blue}{\left(\frac{1}{2} \cdot \left({\left(\sqrt{2}\right)}^{2} \cdot x\right) + \frac{1}{2} \cdot {\left(\sqrt{2}\right)}^{2}\right) - \left(\frac{1}{6} \cdot \left({\left(\sqrt{2}\right)}^{2} \cdot {x}^{3}\right) + 1\right)}\]
Simplified0.0
\[\leadsto \color{blue}{x - \left(x \cdot x\right) \cdot \left(\frac{1}{3} \cdot x\right)}\]
- Recombined 2 regimes into one program.
Final simplification0.0
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -0.0006290873782508793 \lor \neg \left(x \le 0.0009486447256490275\right):\\
\;\;\;\;\sqrt[3]{\left(\sqrt{\frac{2}{e^{-2 \cdot x} + 1}} \cdot \sqrt{\frac{2}{e^{-2 \cdot x} + 1}}\right) \cdot \left(\left(\sqrt{\frac{2}{e^{-2 \cdot x} + 1}} \cdot \sqrt{\frac{2}{e^{-2 \cdot x} + 1}}\right) \cdot \left(\sqrt{\frac{2}{e^{-2 \cdot x} + 1}} \cdot \sqrt{\frac{2}{e^{-2 \cdot x} + 1}}\right)\right)} - 1\\
\mathbf{else}:\\
\;\;\;\;x - \left(x \cdot \frac{1}{3}\right) \cdot \left(x \cdot x\right)\\
\end{array}\]