- Split input into 2 regimes
if N < 8142.718291694942
Initial program 0.1
\[\log \left(N + 1\right) - \log N\]
Initial simplification0.1
\[\leadsto \log \left(1 + N\right) - \log N\]
- Using strategy
rm Applied diff-log0.1
\[\leadsto \color{blue}{\log \left(\frac{1 + N}{N}\right)}\]
- Using strategy
rm Applied add-sqr-sqrt0.1
\[\leadsto \log \color{blue}{\left(\sqrt{\frac{1 + N}{N}} \cdot \sqrt{\frac{1 + N}{N}}\right)}\]
Applied log-prod0.1
\[\leadsto \color{blue}{\log \left(\sqrt{\frac{1 + N}{N}}\right) + \log \left(\sqrt{\frac{1 + N}{N}}\right)}\]
- Using strategy
rm Applied pow1/20.1
\[\leadsto \log \left(\sqrt{\frac{1 + N}{N}}\right) + \log \color{blue}{\left({\left(\frac{1 + N}{N}\right)}^{\frac{1}{2}}\right)}\]
Applied log-pow0.1
\[\leadsto \log \left(\sqrt{\frac{1 + N}{N}}\right) + \color{blue}{\frac{1}{2} \cdot \log \left(\frac{1 + N}{N}\right)}\]
- Using strategy
rm Applied pow1/20.1
\[\leadsto \log \color{blue}{\left({\left(\frac{1 + N}{N}\right)}^{\frac{1}{2}}\right)} + \frac{1}{2} \cdot \log \left(\frac{1 + N}{N}\right)\]
Applied log-pow0.1
\[\leadsto \color{blue}{\frac{1}{2} \cdot \log \left(\frac{1 + N}{N}\right)} + \frac{1}{2} \cdot \log \left(\frac{1 + N}{N}\right)\]
if 8142.718291694942 < N
Initial program 59.6
\[\log \left(N + 1\right) - \log N\]
Initial simplification59.6
\[\leadsto \log \left(1 + N\right) - \log N\]
- Using strategy
rm Applied diff-log59.4
\[\leadsto \color{blue}{\log \left(\frac{1 + N}{N}\right)}\]
Taylor expanded around -inf 0.0
\[\leadsto \color{blue}{\left(\frac{1}{3} \cdot \frac{1}{{N}^{3}} + \frac{1}{N}\right) - \frac{1}{2} \cdot \frac{1}{{N}^{2}}}\]
Simplified0.0
\[\leadsto \color{blue}{\frac{1}{N} - \frac{1}{N \cdot N} \cdot \left(\frac{1}{2} - \frac{\frac{1}{3}}{N}\right)}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;N \le 8142.718291694942:\\
\;\;\;\;\frac{1}{2} \cdot \log \left(\frac{N + 1}{N}\right) + \frac{1}{2} \cdot \log \left(\frac{N + 1}{N}\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{N} - \left(\frac{1}{2} - \frac{\frac{1}{3}}{N}\right) \cdot \frac{1}{N \cdot N}\\
\end{array}\]