- Split input into 2 regimes
if x < -4915.556106227908 or 3851.744190566523 < x
Initial program 60.0
\[\sqrt[3]{x + 1} - \sqrt[3]{x}\]
- Using strategy
rm Applied add-sqr-sqrt61.3
\[\leadsto \color{blue}{\sqrt{\sqrt[3]{x + 1}} \cdot \sqrt{\sqrt[3]{x + 1}}} - \sqrt[3]{x}\]
Taylor expanded around -inf 62.4
\[\leadsto \color{blue}{\left(\frac{5}{81} \cdot \frac{e^{\frac{1}{3} \cdot \left(\log -1 - \log \left(\frac{-1}{x}\right)\right)}}{{x}^{3}} + \frac{1}{3} \cdot \frac{e^{\frac{1}{3} \cdot \left(\log -1 - \log \left(\frac{-1}{x}\right)\right)}}{x}\right) - \frac{1}{9} \cdot \frac{e^{\frac{1}{3} \cdot \left(\log -1 - \log \left(\frac{-1}{x}\right)\right)}}{{x}^{2}}}\]
Simplified0.6
\[\leadsto \color{blue}{\left(\left(\frac{1}{3} + \frac{\frac{-1}{9}}{x}\right) + \frac{\frac{\frac{5}{81}}{x}}{x}\right) \cdot \frac{\sqrt[3]{x}}{x}}\]
if -4915.556106227908 < x < 3851.744190566523
Initial program 0.1
\[\sqrt[3]{x + 1} - \sqrt[3]{x}\]
- Using strategy
rm Applied add-log-exp0.1
\[\leadsto \color{blue}{\log \left(e^{\sqrt[3]{x + 1} - \sqrt[3]{x}}\right)}\]
- Using strategy
rm Applied flip3-+0.1
\[\leadsto \log \left(e^{\sqrt[3]{\color{blue}{\frac{{x}^{3} + {1}^{3}}{x \cdot x + \left(1 \cdot 1 - x \cdot 1\right)}}} - \sqrt[3]{x}}\right)\]
Applied cbrt-div0.1
\[\leadsto \log \left(e^{\color{blue}{\frac{\sqrt[3]{{x}^{3} + {1}^{3}}}{\sqrt[3]{x \cdot x + \left(1 \cdot 1 - x \cdot 1\right)}}} - \sqrt[3]{x}}\right)\]
Simplified0.1
\[\leadsto \log \left(e^{\frac{\color{blue}{\sqrt[3]{1 + {x}^{3}}}}{\sqrt[3]{x \cdot x + \left(1 \cdot 1 - x \cdot 1\right)}} - \sqrt[3]{x}}\right)\]
- Recombined 2 regimes into one program.
Final simplification0.4
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -4915.556106227908 \lor \neg \left(x \le 3851.744190566523\right):\\
\;\;\;\;\frac{\sqrt[3]{x}}{x} \cdot \left(\left(\frac{1}{3} + \frac{\frac{-1}{9}}{x}\right) + \frac{\frac{\frac{5}{81}}{x}}{x}\right)\\
\mathbf{else}:\\
\;\;\;\;\log \left(e^{\frac{\sqrt[3]{{x}^{3} + 1}}{\sqrt[3]{x \cdot x + \left(1 - x\right)}} - \sqrt[3]{x}}\right)\\
\end{array}\]