- Split input into 2 regimes
if x < 0.00021075315610014558
Initial program 59.2
\[e^{x} - 1\]
Taylor expanded around 0 0.0
\[\leadsto \color{blue}{x + \left(\frac{1}{6} \cdot {x}^{3} + \frac{1}{2} \cdot {x}^{2}\right)}\]
Simplified0.0
\[\leadsto \color{blue}{x + \left(x \cdot \frac{1}{6} + \frac{1}{2}\right) \cdot \left(x \cdot x\right)}\]
if 0.00021075315610014558 < x
Initial program 2.9
\[e^{x} - 1\]
- Using strategy
rm Applied add-sqr-sqrt3.8
\[\leadsto \color{blue}{\sqrt{e^{x}} \cdot \sqrt{e^{x}}} - 1\]
Applied difference-of-sqr-13.7
\[\leadsto \color{blue}{\left(\sqrt{e^{x}} + 1\right) \cdot \left(\sqrt{e^{x}} - 1\right)}\]
- Using strategy
rm Applied flip3--5.9
\[\leadsto \left(\sqrt{e^{x}} + 1\right) \cdot \color{blue}{\frac{{\left(\sqrt{e^{x}}\right)}^{3} - {1}^{3}}{\sqrt{e^{x}} \cdot \sqrt{e^{x}} + \left(1 \cdot 1 + \sqrt{e^{x}} \cdot 1\right)}}\]
Applied flip-+6.0
\[\leadsto \color{blue}{\frac{\sqrt{e^{x}} \cdot \sqrt{e^{x}} - 1 \cdot 1}{\sqrt{e^{x}} - 1}} \cdot \frac{{\left(\sqrt{e^{x}}\right)}^{3} - {1}^{3}}{\sqrt{e^{x}} \cdot \sqrt{e^{x}} + \left(1 \cdot 1 + \sqrt{e^{x}} \cdot 1\right)}\]
Applied frac-times6.0
\[\leadsto \color{blue}{\frac{\left(\sqrt{e^{x}} \cdot \sqrt{e^{x}} - 1 \cdot 1\right) \cdot \left({\left(\sqrt{e^{x}}\right)}^{3} - {1}^{3}\right)}{\left(\sqrt{e^{x}} - 1\right) \cdot \left(\sqrt{e^{x}} \cdot \sqrt{e^{x}} + \left(1 \cdot 1 + \sqrt{e^{x}} \cdot 1\right)\right)}}\]
Simplified5.6
\[\leadsto \frac{\color{blue}{\left(\sqrt{e^{x}} \cdot e^{x} - 1\right) \cdot \left(e^{x} - 1\right)}}{\left(\sqrt{e^{x}} - 1\right) \cdot \left(\sqrt{e^{x}} \cdot \sqrt{e^{x}} + \left(1 \cdot 1 + \sqrt{e^{x}} \cdot 1\right)\right)}\]
Simplified5.4
\[\leadsto \frac{\left(\sqrt{e^{x}} \cdot e^{x} - 1\right) \cdot \left(e^{x} - 1\right)}{\color{blue}{\left(\sqrt{e^{x}} - 1\right) \cdot \left(\left(1 + e^{x}\right) + \sqrt{e^{x}}\right)}}\]
- Recombined 2 regimes into one program.
Final simplification0.1
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le 0.00021075315610014558:\\
\;\;\;\;x + \left(x \cdot x\right) \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot x\right)\\
\mathbf{else}:\\
\;\;\;\;\frac{\left(e^{x} - 1\right) \cdot \left(e^{x} \cdot \sqrt{e^{x}} - 1\right)}{\left(\sqrt{e^{x}} - 1\right) \cdot \left(\sqrt{e^{x}} + \left(1 + e^{x}\right)\right)}\\
\end{array}\]