- Split input into 2 regimes
if x < -0.006883813457963097 or 0.006317687962113081 < x
Initial program 0.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied add-cbrt-cube0.0
\[\leadsto \color{blue}{\sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}}} - 1\]
- Using strategy
rm Applied flip3--0.0
\[\leadsto \color{blue}{\frac{{\left(\sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}}\right)}^{3} - {1}^{3}}{\sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}} \cdot \sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}} + \left(1 \cdot 1 + \sqrt[3]{\left(\frac{2}{1 + e^{-2 \cdot x}} \cdot \frac{2}{1 + e^{-2 \cdot x}}\right) \cdot \frac{2}{1 + e^{-2 \cdot x}}} \cdot 1\right)}}\]
Taylor expanded around inf 0.0
\[\leadsto \color{blue}{\frac{8 \cdot \frac{1}{{\left(e^{-2 \cdot x} + 1\right)}^{3}} - 1}{\frac{1}{e^{-2 \cdot x} + 1} \cdot {8}^{\frac{1}{3}} + \left(\frac{1}{{\left(e^{-2 \cdot x} + 1\right)}^{2}} \cdot {64}^{\frac{1}{3}} + 1\right)}}\]
Simplified0.0
\[\leadsto \color{blue}{\frac{\frac{8}{{\left(1 + {\left(e^{-2}\right)}^{x}\right)}^{3}} - 1}{\frac{\sqrt[3]{64}}{{\left(1 + {\left(e^{-2}\right)}^{x}\right)}^{2}} + \left(\frac{\sqrt[3]{8}}{1 + {\left(e^{-2}\right)}^{x}} + 1\right)}}\]
if -0.006883813457963097 < x < 0.006317687962113081
Initial program 59.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
Taylor expanded around 0 0.0
\[\leadsto \color{blue}{\left(x + \frac{2}{15} \cdot {x}^{5}\right) - \frac{1}{3} \cdot {x}^{3}}\]
- Recombined 2 regimes into one program.
Final simplification0.0
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -0.006883813457963097 \lor \neg \left(x \le 0.006317687962113081\right):\\
\;\;\;\;\frac{\frac{8}{{\left({\left(e^{-2}\right)}^{x} + 1\right)}^{3}} - 1}{\frac{\sqrt[3]{64}}{{\left({\left(e^{-2}\right)}^{x} + 1\right)}^{2}} + \left(\frac{\sqrt[3]{8}}{{\left(e^{-2}\right)}^{x} + 1} + 1\right)}\\
\mathbf{else}:\\
\;\;\;\;\left(x + {x}^{5} \cdot \frac{2}{15}\right) - \frac{1}{3} \cdot {x}^{3}\\
\end{array}\]