Average Error: 40.3 → 0.3
Time: 7.3s
Precision: 64
Internal Precision: 1344
\[\frac{e^{x} - 1}{x}\]
↓
\[\begin{array}{l} \mathbf{if}\;x \le -0.00019083026175142057:\\ \;\;\;\;e^{x} \cdot \frac{1}{x} - \frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\left(1 + {x}^{2} \cdot \frac{1}{6}\right) + x \cdot \frac{1}{2}\\ \end{array}\]

Error

Bits error versus x

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original40.3
Target39.5
Herbie0.3
\[\begin{array}{l} \mathbf{if}\;x \lt 1 \land x \gt -1:\\ \;\;\;\;\frac{e^{x} - 1}{\log \left(e^{x}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{e^{x} - 1}{x}\\ \end{array}\]

Derivation

  1. Split input into 2 regimes

  2. if x < -0.00019083026175142057

    1. Initial program 0.1

      \[\frac{e^{x} - 1}{x}\]
    2. Using strategy rm

    3. Applied div-sub0.1

      \[\leadsto \color{blue}{\frac{e^{x}}{x} - \frac{1}{x}}\]
    4. Using strategy rm

    5. Applied div-inv0.1

      \[\leadsto \color{blue}{e^{x} \cdot \frac{1}{x}} - \frac{1}{x}\]

    if -0.00019083026175142057 < x

    1. Initial program 60.3

      \[\frac{e^{x} - 1}{x}\]

    2. Taylor expanded around 0 0.4

      \[\leadsto \color{blue}{\frac{1}{2} \cdot x + \left(\frac{1}{6} \cdot {x}^{2} + 1\right)}\]
  3. Recombined 2 regimes into one program.

  4. Final simplification0.3

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \le -0.00019083026175142057:\\ \;\;\;\;e^{x} \cdot \frac{1}{x} - \frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\left(1 + {x}^{2} \cdot \frac{1}{6}\right) + x \cdot \frac{1}{2}\\ \end{array}\]

Runtime

Time bar (total: 7.3s)Debug logProfile

herbie shell --seed 2018220 
(FPCore (x)
  :name "Kahan's exp quotient"

  :herbie-target
  (if (and (< x 1) (> x -1)) (/ (- (exp x) 1) (log (exp x))) (/ (- (exp x) 1) x))

  (/ (- (exp x) 1) x))