- Split input into 2 regimes
if x < -0.00744990134718954 or 0.007411501740066481 < x
Initial program 0.0
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied add-log-exp0.0
\[\leadsto \color{blue}{\log \left(e^{\frac{2}{1 + e^{-2 \cdot x}}}\right)} - 1\]
- Using strategy
rm Applied flip3--0.0
\[\leadsto \color{blue}{\frac{{\left(\log \left(e^{\frac{2}{1 + e^{-2 \cdot x}}}\right)\right)}^{3} - {1}^{3}}{\log \left(e^{\frac{2}{1 + e^{-2 \cdot x}}}\right) \cdot \log \left(e^{\frac{2}{1 + e^{-2 \cdot x}}}\right) + \left(1 \cdot 1 + \log \left(e^{\frac{2}{1 + e^{-2 \cdot x}}}\right) \cdot 1\right)}}\]
if -0.00744990134718954 < x < 0.007411501740066481
Initial program 59.1
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
Taylor expanded around 0 0.0
\[\leadsto \color{blue}{\left(x + \frac{2}{15} \cdot {x}^{5}\right) - \frac{1}{3} \cdot {x}^{3}}\]
- Using strategy
rm Applied associate--l+0.0
\[\leadsto \color{blue}{x + \left(\frac{2}{15} \cdot {x}^{5} - \frac{1}{3} \cdot {x}^{3}\right)}\]
- Recombined 2 regimes into one program.
Final simplification0.0
\[\leadsto \begin{array}{l}
\mathbf{if}\;x \le -0.00744990134718954 \lor \neg \left(x \le 0.007411501740066481\right):\\
\;\;\;\;\frac{{\left(\log \left(e^{\frac{2}{e^{-2 \cdot x} + 1}}\right)\right)}^{3} - {1}^{3}}{\log \left(e^{\frac{2}{e^{-2 \cdot x} + 1}}\right) \cdot \log \left(e^{\frac{2}{e^{-2 \cdot x} + 1}}\right) + \left(1 + \log \left(e^{\frac{2}{e^{-2 \cdot x} + 1}}\right)\right)}\\
\mathbf{else}:\\
\;\;\;\;\left(\frac{2}{15} \cdot {x}^{5} - {x}^{3} \cdot \frac{1}{3}\right) + x\\
\end{array}\]