Initial program 1.8
\[\frac{\pi}{\sin \left(\pi \cdot z\right)} \cdot \left(\left(\left(\sqrt{\pi \cdot 2} \cdot {\left(\left(\left(\left(1 - z\right) - 1\right) + 7\right) + 0.5\right)}^{\left(\left(\left(1 - z\right) - 1\right) + 0.5\right)}\right) \cdot e^{-\left(\left(\left(\left(1 - z\right) - 1\right) + 7\right) + 0.5\right)}\right) \cdot \left(\left(\left(\left(\left(\left(\left(\left(0.9999999999998099 + \frac{676.5203681218851}{\left(\left(1 - z\right) - 1\right) + 1}\right) + \frac{-1259.1392167224028}{\left(\left(1 - z\right) - 1\right) + 2}\right) + \frac{771.3234287776531}{\left(\left(1 - z\right) - 1\right) + 3}\right) + \frac{-176.6150291621406}{\left(\left(1 - z\right) - 1\right) + 4}\right) + \frac{12.507343278686905}{\left(\left(1 - z\right) - 1\right) + 5}\right) + \frac{-0.13857109526572012}{\left(\left(1 - z\right) - 1\right) + 6}\right) + \frac{9.984369578019572 \cdot 10^{-06}}{\left(\left(1 - z\right) - 1\right) + 7}\right) + \frac{1.5056327351493116 \cdot 10^{-07}}{\left(\left(1 - z\right) - 1\right) + 8}\right)\right)\]
Initial simplification1.4
\[\leadsto \left(\left(\frac{\pi}{\sin \left(\pi \cdot z\right)} \cdot \left(\sqrt{2 \cdot \pi} \cdot {\left(7 + \left(\left(1 - z\right) - \left(1 - 0.5\right)\right)\right)}^{\left(\left(1 - z\right) - \left(1 - 0.5\right)\right)}\right)\right) \cdot \frac{1}{e^{7 + \left(\left(1 - z\right) - \left(1 - 0.5\right)\right)}}\right) \cdot \left(\left(\left(0.9999999999998099 + \left(\frac{676.5203681218851}{\left(1 - z\right) - 0} + \frac{-1259.1392167224028}{\left(2 + 1\right) - \left(z + 1\right)}\right)\right) + \left(\left(\frac{771.3234287776531}{\left(1 - z\right) - \left(1 - 3\right)} + \frac{-176.6150291621406}{\left(4 + 1\right) - \left(z + 1\right)}\right) + \left(\frac{-0.13857109526572012}{\left(6 + 1\right) - \left(z + 1\right)} + \frac{12.507343278686905}{\left(1 - z\right) - \left(1 - 5\right)}\right)\right)\right) + \left(\frac{1.5056327351493116 \cdot 10^{-07}}{\left(8 + 1\right) - \left(z + 1\right)} + \frac{9.984369578019572 \cdot 10^{-06}}{\left(7 + 1\right) - \left(z + 1\right)}\right)\right)\]
Simplified0.6
\[\leadsto \color{blue}{\frac{{\left(\left(\left(7 + 1\right) - \left(z + 1\right)\right) + 0.5\right)}^{\left(\left(1 - z\right) - \left(1 - 0.5\right)\right)} \cdot \frac{\pi \cdot \sqrt{2 \cdot \pi}}{\sin \left(\pi \cdot z\right)}}{e^{\left(\left(7 + 1\right) - \left(z + 1\right)\right) + 0.5}} \cdot \left(\left(\left(\frac{-176.6150291621406}{\left(4 + 1\right) - \left(z + 1\right)} + \frac{771.3234287776531}{\left(1 - z\right) - \left(1 - 3\right)}\right) + \left(\frac{12.507343278686905}{\left(1 - z\right) - \left(1 - 5\right)} + \frac{-0.13857109526572012}{\left(6 + 1\right) - \left(z + 1\right)}\right)\right) + \left(\left(\left(0.9999999999998099 + \frac{676.5203681218851}{1 - z}\right) + \frac{-1259.1392167224028}{\left(2 + 1\right) - \left(z + 1\right)}\right) + \left(\frac{1.5056327351493116 \cdot 10^{-07}}{\left(8 + 1\right) - \left(1 + z\right)} + \frac{9.984369578019572 \cdot 10^{-06}}{\left(7 + 1\right) - \left(z + 1\right)}\right)\right)\right)}\]
Final simplification0.6
\[\leadsto \left(\left(\left(\frac{12.507343278686905}{\left(1 - z\right) - \left(1 - 5\right)} + \frac{-0.13857109526572012}{\left(6 + 1\right) - \left(1 + z\right)}\right) + \left(\frac{771.3234287776531}{\left(1 - z\right) - \left(1 - 3\right)} + \frac{-176.6150291621406}{\left(1 + 4\right) - \left(1 + z\right)}\right)\right) + \left(\left(\frac{1.5056327351493116 \cdot 10^{-07}}{\left(1 + 8\right) - \left(1 + z\right)} + \frac{9.984369578019572 \cdot 10^{-06}}{\left(1 + 7\right) - \left(1 + z\right)}\right) + \left(\left(0.9999999999998099 + \frac{676.5203681218851}{1 - z}\right) + \frac{-1259.1392167224028}{\left(2 + 1\right) - \left(1 + z\right)}\right)\right)\right) \cdot \frac{\frac{\sqrt{2 \cdot \pi} \cdot \pi}{\sin \left(\pi \cdot z\right)} \cdot {\left(\left(\left(1 + 7\right) - \left(1 + z\right)\right) + 0.5\right)}^{\left(\left(1 - z\right) - \left(1 - 0.5\right)\right)}}{e^{\left(\left(1 + 7\right) - \left(1 + z\right)\right) + 0.5}}\]