- Split input into 3 regimes
if (- (/ 2 (+ 1 (exp (* -2 x)))) 1) < -1.9998338867390905e-05
Initial program 0.1
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied add-sqr-sqrt0.1
\[\leadsto \frac{2}{\color{blue}{\sqrt{1 + e^{-2 \cdot x}} \cdot \sqrt{1 + e^{-2 \cdot x}}}} - 1\]
Applied associate-/r*0.1
\[\leadsto \color{blue}{\frac{\frac{2}{\sqrt{1 + e^{-2 \cdot x}}}}{\sqrt{1 + e^{-2 \cdot x}}}} - 1\]
if -1.9998338867390905e-05 < (- (/ 2 (+ 1 (exp (* -2 x)))) 1) < 5.071281949931006e-08
Initial program 59.6
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
Taylor expanded around 0 0
\[\leadsto \color{blue}{\left(\frac{2}{15} \cdot {x}^{5} + x\right) - \frac{1}{3} \cdot {x}^{3}}\]
if 5.071281949931006e-08 < (- (/ 2 (+ 1 (exp (* -2 x)))) 1)
Initial program 0.2
\[\frac{2}{1 + e^{-2 \cdot x}} - 1\]
- Using strategy
rm Applied flip3-+0.2
\[\leadsto \frac{2}{\color{blue}{\frac{{1}^{3} + {\left(e^{-2 \cdot x}\right)}^{3}}{1 \cdot 1 + \left(e^{-2 \cdot x} \cdot e^{-2 \cdot x} - 1 \cdot e^{-2 \cdot x}\right)}}} - 1\]
Applied associate-/r/0.2
\[\leadsto \color{blue}{\frac{2}{{1}^{3} + {\left(e^{-2 \cdot x}\right)}^{3}} \cdot \left(1 \cdot 1 + \left(e^{-2 \cdot x} \cdot e^{-2 \cdot x} - 1 \cdot e^{-2 \cdot x}\right)\right)} - 1\]
Applied simplify0.2
\[\leadsto \color{blue}{\frac{2}{{\left(e^{x \cdot -2}\right)}^{3} + 1}} \cdot \left(1 \cdot 1 + \left(e^{-2 \cdot x} \cdot e^{-2 \cdot x} - 1 \cdot e^{-2 \cdot x}\right)\right) - 1\]
- Recombined 3 regimes into one program.
Applied simplify0.1
\[\leadsto \color{blue}{\begin{array}{l}
\mathbf{if}\;\frac{2}{1 + e^{-2 \cdot x}} - 1 \le -1.9998338867390905 \cdot 10^{-05}:\\
\;\;\;\;\frac{\frac{2}{\sqrt{1 + e^{-2 \cdot x}}}}{\sqrt{1 + e^{-2 \cdot x}}} - 1\\
\mathbf{if}\;\frac{2}{1 + e^{-2 \cdot x}} - 1 \le 5.071281949931006 \cdot 10^{-08}:\\
\;\;\;\;\left(\frac{2}{15} \cdot {x}^{5} + x\right) - \frac{1}{3} \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\frac{2}{{\left(e^{-2 \cdot x}\right)}^{3} + 1} \cdot \left(1 + \left(e^{-2 \cdot x} \cdot e^{-2 \cdot x} - e^{-2 \cdot x}\right)\right) - 1\\
\end{array}}\]