- Started with
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
29.6
- Using strategy
rm 29.6
- Applied div-inv to get
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{red}{\frac{i}{n}}} \leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{i \cdot \frac{1}{n}}}\]
29.6
- Applied *-un-lft-identity to get
\[100 \cdot \frac{\color{red}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i \cdot \frac{1}{n}} \leadsto 100 \cdot \frac{\color{blue}{1 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i \cdot \frac{1}{n}}\]
29.6
- Applied times-frac to get
\[100 \cdot \color{red}{\frac{1 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i \cdot \frac{1}{n}}} \leadsto 100 \cdot \color{blue}{\left(\frac{1}{i} \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{1}{n}}\right)}\]
29.9
- Applied taylor to get
\[100 \cdot \left(\frac{1}{i} \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{1}{n}}\right) \leadsto 100 \cdot \left(\frac{1}{i} \cdot \frac{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}{\frac{1}{n}}\right)\]
0.6
- Taylor expanded around 0 to get
\[100 \cdot \left(\frac{1}{i} \cdot \frac{\color{red}{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}}{\frac{1}{n}}\right) \leadsto 100 \cdot \left(\frac{1}{i} \cdot \frac{\color{blue}{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}}{\frac{1}{n}}\right)\]
0.6
- Applied simplify to get
\[100 \cdot \left(\frac{1}{i} \cdot \frac{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}{\frac{1}{n}}\right) \leadsto \frac{(\frac{1}{2} * \left(i \cdot i\right) + \left((\frac{1}{6} * \left({i}^3\right) + i)_*\right))_*}{\frac{1}{n}} \cdot \frac{100}{i}\]
3.8
- Applied final simplification
- Started with
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
24.2
- Applied taylor to get
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
19.0
- Taylor expanded around inf to get
\[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
19.0
- Applied simplify to get
\[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
19.8
- Applied taylor to get
\[\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}\]
0.3
- Taylor expanded around inf to get
\[\color{red}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}} \leadsto \color{blue}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}}\]
0.3
- Applied simplify to get
\[100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\left(\left(-\log n\right) - \left(-\log i\right)\right) \cdot n} - 1)^*\]
1.1
- Applied final simplification