- Started with
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
61.8
- Using strategy
rm 61.8
- Applied add-exp-log to get
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{red}{\frac{i}{n}}} \leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{e^{\log \left(\frac{i}{n}\right)}}}\]
62.0
- Applied add-exp-log to get
\[100 \cdot \frac{\color{red}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{e^{\log \left(\frac{i}{n}\right)}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}}{e^{\log \left(\frac{i}{n}\right)}}\]
62.0
- Applied div-exp to get
\[100 \cdot \color{red}{\frac{e^{\log \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{e^{\log \left(\frac{i}{n}\right)}}} \leadsto 100 \cdot \color{blue}{e^{\log \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) - \log \left(\frac{i}{n}\right)}}\]
62.0
- Applied taylor to get
\[100 \cdot e^{\log \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) - \log \left(\frac{i}{n}\right)} \leadsto 100 \cdot \left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)\]
0.0
- Taylor expanded around 0 to get
\[100 \cdot \color{red}{\left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)} \leadsto 100 \cdot \color{blue}{\left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)}\]
0.0
- Applied simplify to get
\[100 \cdot \left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right) \leadsto \left(\left(i \cdot \frac{1}{2}\right) \cdot n + \left(\left(i \cdot i\right) \cdot \left(n \cdot \frac{1}{6}\right) + n\right)\right) \cdot 100\]
0.0
- Applied final simplification
- Started with
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
55.0
- Applied taylor to get
\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
58.4
- Taylor expanded around 0 to get
\[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
58.4
- Applied simplify to get
\[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\frac{i}{n}}}\]
46.6
- Using strategy
rm 46.6
- Applied add-cube-cbrt to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{red}{\frac{i}{n}}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{blue}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}}\]
46.6
- Applied add-cube-cbrt to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{red}{i \cdot 100}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{blue}{{\left(\sqrt[3]{i \cdot 100}\right)}^3}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}\]
46.6
- Applied cube-undiv to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot \color{red}{\frac{{\left(\sqrt[3]{i \cdot 100}\right)}^3}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \color{blue}{{\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3}\]
46.6
- Applied taylor to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
15.7
- Taylor expanded around inf to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{red}{\sqrt[3]{\frac{100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{blue}{\sqrt[3]{\frac{100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
15.7
- Applied simplify to get
\[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \frac{\frac{100}{i}}{\frac{i}{n}} \cdot \left(i \cdot \frac{1}{2} + 1\right)\]
15.1
- Applied final simplification