if i < -3.133404071892548e-152

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   37.6
2. Using strategy rm
   37.6
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   37.6
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   37.6
5. Applied expm1-def to get
   \[100 \cdot \frac{\color{red}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{(e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1)^*}}{\frac{i}{n}}\]
   31.9
6. Applied taylor to get
   \[100 \cdot \frac{(e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1)^*}{\frac{i}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}\]
   32.9
7. Taylor expanded around 0 to get
   \[100 \cdot \color{red}{\frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}} \leadsto 100 \cdot \color{blue}{\frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}}\]
   32.9
8. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\log_* (1 + \frac{i}{n}) \cdot n} - 1)^*\]
   4.2

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9. Applied final simplification

if -3.133404071892548e-152 < i < 48071161730.91927

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   61.7
2. Using strategy rm
   61.7
3. Applied div-sub to get
   \[100 \cdot \color{red}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)}\]
   61.7
4. Applied simplify to get
   \[100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \color{red}{\frac{1}{\frac{i}{n}}}\right) \leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \color{blue}{\frac{n}{i}}\right)\]
   61.8
5. Applied taylor to get
   \[100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{n}{i}\right) \leadsto 100 \cdot \left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)\]
   0.0
6. Taylor expanded around 0 to get
   \[100 \cdot \color{red}{\left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)} \leadsto 100 \cdot \color{blue}{\left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right)}\]
   0.0
7. Applied simplify to get
   \[100 \cdot \left(n + \left(\frac{1}{6} \cdot \left(n \cdot {i}^2\right) + \frac{1}{2} \cdot \left(n \cdot i\right)\right)\right) \leadsto (100 * \left((\left(i \cdot i\right) * \left(n \cdot \frac{1}{6}\right) + n)_*\right) + \left(\left(100 \cdot i\right) \cdot \left(n \cdot \frac{1}{2}\right)\right))_*\]
   0.0

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8. Applied final simplification

if 48071161730.91927 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   51.3
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
   39.0
3. Taylor expanded around inf to get
   \[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
   39.0
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
   39.3
5. Applied taylor to get
   \[\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}\]
   0.3
6. Taylor expanded around inf to get
   \[\color{red}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}} \leadsto \color{blue}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}}\]
   0.3
7. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\left(\left(-\log n\right) - \left(-\log i\right)\right) \cdot n} - 1)^*\]
   0.5

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8. Applied final simplification