if i < -0.002604022f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   10.4
2. Using strategy rm
   10.4
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   10.4
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   10.4
5. Applied simplify to get
   \[100 \cdot \frac{e^{\color{red}{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\color{blue}{\log_* (1 + \frac{i}{n}) \cdot n}} - 1}{\frac{i}{n}}\]
   2.3

if -0.002604022f0 < i < 9.528385f-15

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   29.6
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
   28.0
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
   28.0
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \frac{100}{\frac{i}{n}}}\]
   8.4
5. Applied taylor to get
   \[(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \frac{100}{\frac{i}{n}} \leadsto 100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot n}{i}\]
   0.0
6. Taylor expanded around 0 to get
   \[\color{red}{100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot n}{i}} \leadsto \color{blue}{100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot n}{i}}\]
   0.0

if 9.528385f-15 < i < 59.312374f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   25.0
2. Using strategy rm
   25.0
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   25.0
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   25.0
5. Applied expm1-def to get
   \[100 \cdot \frac{\color{red}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{(e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1)^*}}{\frac{i}{n}}\]
   19.2
6. Applied taylor to get
   \[100 \cdot \frac{(e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1)^*}{\frac{i}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}\]
   19.3
7. Taylor expanded around 0 to get
   \[100 \cdot \color{red}{\frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}} \leadsto 100 \cdot \color{blue}{\frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i}}\]
   19.3
8. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{\log \left(\frac{i}{n} + 1\right) \cdot n} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\log_* (1 + \frac{i}{n}) \cdot n} - 1)^*\]
   3.1

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9. Applied final simplification

if 59.312374f0 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   23.5
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
   20.7
3. Taylor expanded around inf to get
   \[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
   20.7
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
   21.5
5. Applied taylor to get
   \[\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}\]
   0.2
6. Taylor expanded around inf to get
   \[\color{red}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}} \leadsto \color{blue}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}}\]
   0.2
7. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\left(\left(-\log n\right) - \left(-\log i\right)\right) \cdot n} - 1)^*\]
   1.4

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8. Applied final simplification