if x < -0.03550508f0

1. Started with
   \[\frac{e^{x} - 1}{x}\]
   0.1

if -0.03550508f0 < x

1. Started with
   \[\frac{e^{x} - 1}{x}\]
   26.6
2. Using strategy rm
   26.6
3. Applied add-sqr-sqrt to get
   \[\frac{\color{red}{e^{x}} - 1}{x} \leadsto \frac{\color{blue}{{\left(\sqrt{e^{x}}\right)}^2} - 1}{x}\]
   26.8
4. Applied difference-of-sqr-1 to get
   \[\frac{\color{red}{{\left(\sqrt{e^{x}}\right)}^2 - 1}}{x} \leadsto \frac{\color{blue}{\left(\sqrt{e^{x}} + 1\right) \cdot \left(\sqrt{e^{x}} - 1\right)}}{x}\]
   26.8
5. Applied taylor to get
   \[\frac{\left(\sqrt{e^{x}} + 1\right) \cdot \left(\sqrt{e^{x}} - 1\right)}{x} \leadsto \frac{\left(\sqrt{e^{x}} + 1\right) \cdot \left(\frac{1}{8} \cdot {x}^2 + \left(\frac{1}{48} \cdot {x}^{3} + \frac{1}{2} \cdot x\right)\right)}{x}\]
   0.1
6. Taylor expanded around 0 to get
   \[\frac{\left(\sqrt{e^{x}} + 1\right) \cdot \color{red}{\left(\frac{1}{8} \cdot {x}^2 + \left(\frac{1}{48} \cdot {x}^{3} + \frac{1}{2} \cdot x\right)\right)}}{x} \leadsto \frac{\left(\sqrt{e^{x}} + 1\right) \cdot \color{blue}{\left(\frac{1}{8} \cdot {x}^2 + \left(\frac{1}{48} \cdot {x}^{3} + \frac{1}{2} \cdot x\right)\right)}}{x}\]
   0.1
7. Applied simplify to get
   \[\frac{\left(\sqrt{e^{x}} + 1\right) \cdot \left(\frac{1}{8} \cdot {x}^2 + \left(\frac{1}{48} \cdot {x}^{3} + \frac{1}{2} \cdot x\right)\right)}{x} \leadsto \frac{\left({x}^3 \cdot \frac{1}{48} + {x}^2 \cdot \frac{1}{8}\right) + x \cdot \frac{1}{2}}{\frac{x}{\sqrt{e^{x}} + 1}}\]
   0.2

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8. Applied final simplification
9. Applied simplify to get
   \[\color{red}{\frac{\left({x}^3 \cdot \frac{1}{48} + {x}^2 \cdot \frac{1}{8}\right) + x \cdot \frac{1}{2}}{\frac{x}{\sqrt{e^{x}} + 1}}} \leadsto \color{blue}{\frac{x \cdot \left(\left(x \cdot \frac{1}{8} + \frac{1}{2}\right) + {x}^2 \cdot \frac{1}{48}\right)}{\frac{x}{1 + \sqrt{e^{x}}}}}\]
   0.2