\(\left(b - \frac{{b}^{\left(-a\right)}}{e^{\left(a \cdot \frac{1}{3}\right) \cdot {b}^2}}\right) - \sin^{-1} b\)
- Started with
\[b - \left({\left(\cot b\right)}^{a} + \sin^{-1} b\right)\]
2.6
- Using strategy
rm 2.6
- Applied add-exp-log to get
\[b - \left({\color{red}{\left(\cot b\right)}}^{a} + \sin^{-1} b\right) \leadsto b - \left({\color{blue}{\left(e^{\log \left(\cot b\right)}\right)}}^{a} + \sin^{-1} b\right)\]
7.5
- Applied pow-exp to get
\[b - \left(\color{red}{{\left(e^{\log \left(\cot b\right)}\right)}^{a}} + \sin^{-1} b\right) \leadsto b - \left(\color{blue}{e^{\log \left(\cot b\right) \cdot a}} + \sin^{-1} b\right)\]
7.5
- Applied taylor to get
\[b - \left(e^{\log \left(\cot b\right) \cdot a} + \sin^{-1} b\right) \leadsto b - \left(e^{-\left(a \cdot \log b + \frac{1}{3} \cdot \left({b}^2 \cdot a\right)\right)} + \sin^{-1} b\right)\]
7.5
- Taylor expanded around 0 to get
\[b - \left(e^{\color{red}{-\left(a \cdot \log b + \frac{1}{3} \cdot \left({b}^2 \cdot a\right)\right)}} + \sin^{-1} b\right) \leadsto b - \left(e^{\color{blue}{-\left(a \cdot \log b + \frac{1}{3} \cdot \left({b}^2 \cdot a\right)\right)}} + \sin^{-1} b\right)\]
7.5
- Applied simplify to get
\[b - \left(e^{-\left(a \cdot \log b + \frac{1}{3} \cdot \left({b}^2 \cdot a\right)\right)} + \sin^{-1} b\right) \leadsto \left(b - \frac{{b}^{\left(-a\right)}}{e^{\left(a \cdot \frac{1}{3}\right) \cdot {b}^2}}\right) - \sin^{-1} b\]
3.0
- Applied final simplification