if i < 5.2930678f+26

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   22.8
2. Using strategy rm
   22.8
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   22.8
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   22.8
5. Applied expm1-def to get
   \[100 \cdot \frac{\color{red}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{(e^{\log \left(1 + \frac{i}{n}\right) \cdot n} - 1)^*}}{\frac{i}{n}}\]
   19.0
6. Using strategy rm
   19.0
7. Applied expm1-log1p-u to get
   \[100 \cdot \frac{(e^{\color{red}{\log \left(1 + \frac{i}{n}\right)} \cdot n} - 1)^*}{\frac{i}{n}} \leadsto 100 \cdot \frac{(e^{\color{blue}{(e^{\log_* (1 + \log \left(1 + \frac{i}{n}\right))} - 1)^*} \cdot n} - 1)^*}{\frac{i}{n}}\]
   19.0
8. Applied simplify to get
   \[100 \cdot \frac{(e^{(e^{\color{red}{\log_* (1 + \log \left(1 + \frac{i}{n}\right))}} - 1)^* \cdot n} - 1)^*}{\frac{i}{n}} \leadsto 100 \cdot \frac{(e^{(e^{\color{blue}{\log_* (1 + \log_* (1 + \frac{i}{n}))}} - 1)^* \cdot n} - 1)^*}{\frac{i}{n}}\]
   4.7

if 5.2930678f+26 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   30.8
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
   13.4
3. Taylor expanded around inf to get
   \[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
   13.4
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
   1.6