\[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
Test:
Numeric.SpecFunctions:incompleteBetaWorker from math-functions-0.1.5.2
Bits:
128 bits
Bits error versus x
Bits error versus y
Bits error versus z
Bits error versus t
Bits error versus a
Bits error versus b
Time: 59.6 s
Input Error: 14.2
Output Error: 1.9
Log:
Profile: 🕒
\(\begin{cases} \frac{\frac{x}{e^{\frac{1}{b}}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}} & \text{when } b \le -15.124314f0 \\ \frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{t} \cdot {a}^{\left(-1.0\right)}}} & \text{when } b \le 3126.1138f0 \\ \frac{\frac{x}{e^{b}}}{\left(y \cdot a\right) \cdot \left(1 - (\left(-\log z\right) * \left(\frac{1}{y}\right) + \left(-\frac{\log a}{t}\right))_*\right)} & \text{otherwise} \end{cases}\)

    if b < -15.124314f0

    1. Started with
      \[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
      23.8
    2. Applied simplify to get
      \[\color{red}{\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}} \leadsto \color{blue}{\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}}}\]
      30.0
    3. Applied taylor to get
      \[\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}} \leadsto \frac{\frac{x}{e^{\frac{1}{b}}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}}\]
      1.8
    4. Taylor expanded around inf to get
      \[\frac{\color{red}{\frac{x}{e^{\frac{1}{b}}}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}} \leadsto \frac{\color{blue}{\frac{x}{e^{\frac{1}{b}}}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}}\]
      1.8

    if -15.124314f0 < b < 3126.1138f0

    1. Started with
      \[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
      13.8
    2. Applied simplify to get
      \[\color{red}{\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}} \leadsto \color{blue}{\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}}}\]
      1.8
    3. Using strategy rm
      1.8
    4. Applied sub-neg to get
      \[\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\color{red}{\left(t - 1.0\right)}}}} \leadsto \frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\color{blue}{\left(t + \left(-1.0\right)\right)}}}}\]
      1.8
    5. Applied unpow-prod-up to get
      \[\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{\color{red}{{a}^{\left(t + \left(-1.0\right)\right)}}}} \leadsto \frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{\color{blue}{{a}^{t} \cdot {a}^{\left(-1.0\right)}}}}\]
      1.7

    if 3126.1138f0 < b

    1. Started with
      \[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
      6.5
    2. Applied simplify to get
      \[\color{red}{\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}} \leadsto \color{blue}{\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}}}\]
      13.9
    3. Applied taylor to get
      \[\frac{\frac{x}{e^{b}}}{\frac{\frac{y}{{z}^{y}}}{{a}^{\left(t - 1.0\right)}}} \leadsto \frac{\frac{x}{e^{b}}}{y \cdot a - \left({y}^2 \cdot \left(\log z \cdot a\right) + y \cdot \left(\log a \cdot \left(a \cdot t\right)\right)\right)}\]
      2.7
    4. Taylor expanded around 0 to get
      \[\frac{\frac{x}{e^{b}}}{\color{red}{y \cdot a - \left({y}^2 \cdot \left(\log z \cdot a\right) + y \cdot \left(\log a \cdot \left(a \cdot t\right)\right)\right)}} \leadsto \frac{\frac{x}{e^{b}}}{\color{blue}{y \cdot a - \left({y}^2 \cdot \left(\log z \cdot a\right) + y \cdot \left(\log a \cdot \left(a \cdot t\right)\right)\right)}}\]
      2.7
    5. Applied simplify to get
      \[\color{red}{\frac{\frac{x}{e^{b}}}{y \cdot a - \left({y}^2 \cdot \left(\log z \cdot a\right) + y \cdot \left(\log a \cdot \left(a \cdot t\right)\right)\right)}} \leadsto \color{blue}{\frac{\frac{x}{e^{b}}}{y \cdot a - \left(y \cdot a\right) \cdot (\left(\log z\right) * y + \left(t \cdot \log a\right))_*}}\]
      4.4
    6. Applied taylor to get
      \[\frac{\frac{x}{e^{b}}}{y \cdot a - \left(y \cdot a\right) \cdot (\left(\log z\right) * y + \left(t \cdot \log a\right))_*} \leadsto \frac{\frac{x}{e^{b}}}{y \cdot \left(\left(1 - (\left(\log \left(\frac{1}{z}\right)\right) * \left(\frac{1}{y}\right) + \left(\frac{\log \left(\frac{1}{a}\right)}{t}\right))_*\right) \cdot a\right)}\]
      0
    7. Taylor expanded around inf to get
      \[\frac{\frac{x}{e^{b}}}{\color{red}{y \cdot \left(\left(1 - (\left(\log \left(\frac{1}{z}\right)\right) * \left(\frac{1}{y}\right) + \left(\frac{\log \left(\frac{1}{a}\right)}{t}\right))_*\right) \cdot a\right)}} \leadsto \frac{\frac{x}{e^{b}}}{\color{blue}{y \cdot \left(\left(1 - (\left(\log \left(\frac{1}{z}\right)\right) * \left(\frac{1}{y}\right) + \left(\frac{\log \left(\frac{1}{a}\right)}{t}\right))_*\right) \cdot a\right)}}\]
      0
    8. Applied simplify to get
      \[\frac{\frac{x}{e^{b}}}{y \cdot \left(\left(1 - (\left(\log \left(\frac{1}{z}\right)\right) * \left(\frac{1}{y}\right) + \left(\frac{\log \left(\frac{1}{a}\right)}{t}\right))_*\right) \cdot a\right)} \leadsto \frac{\frac{x}{e^{b}}}{\left(y \cdot a\right) \cdot \left(1 - (\left(-\log z\right) * \left(\frac{1}{y}\right) + \left(-\frac{\log a}{t}\right))_*\right)}\]
      2.3

    9. Applied final simplification

  1. Removed slow pow expressions

Original test:


(lambda ((x default) (y default) (z default) (t default) (a default) (b default))
  #:name "Numeric.SpecFunctions:incompleteBetaWorker from math-functions-0.1.5.2"
  (/ (* x (exp (- (+ (* y (log z)) (* (- t 1.0) (log a))) b))) y))