if i < -1.5462575557939344e-122 or 7.652871194551478e-173 < i < 3.418504310435436e-09

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   42.4
2. Using strategy rm
   42.4
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   42.4
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   42.4
5. Applied simplify to get
   \[100 \cdot \frac{e^{\color{red}{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\color{blue}{\log_* (1 + \frac{i}{n}) \cdot n}} - 1}{\frac{i}{n}}\]
   31.0
6. Applied taylor to get
   \[100 \cdot \frac{e^{\log_* (1 + \frac{i}{n}) \cdot n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{n \cdot \log_* (1 + \frac{i}{n})} - 1}{\frac{i}{n}}\]
   31.0
7. Taylor expanded around 0 to get
   \[100 \cdot \frac{e^{\color{red}{n \cdot \log_* (1 + \frac{i}{n})}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\color{blue}{n \cdot \log_* (1 + \frac{i}{n})}} - 1}{\frac{i}{n}}\]
   31.0
8. Applied simplify to get
   \[100 \cdot \frac{e^{n \cdot \log_* (1 + \frac{i}{n})} - 1}{\frac{i}{n}} \leadsto \frac{(e^{n \cdot \log_* (1 + \frac{i}{n})} - 1)^*}{\frac{\frac{i}{n}}{100}}\]
   4.7

---

9. Applied final simplification

if -1.5462575557939344e-122 < i < 7.652871194551478e-173

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   61.6
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
   61.4
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
   61.4
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \frac{100}{\frac{i}{n}}}\]
   21.7
5. Using strategy rm
   21.7
6. Applied associate-/r/ to get
   \[(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \color{red}{\frac{100}{\frac{i}{n}}} \leadsto (i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \color{blue}{\left(\frac{100}{i} \cdot n\right)}\]
   21.9
7. Applied associate-*r* to get
   \[\color{red}{(i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \left(\frac{100}{i} \cdot n\right)} \leadsto \color{blue}{\left((i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \frac{100}{i}\right) \cdot n}\]
   0.7
8. Applied taylor to get
   \[\left((i * \left(\frac{1}{2} \cdot i\right) + i)_* \cdot \frac{100}{i}\right) \cdot n \leadsto \left(100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_*}{i}\right) \cdot n\]
   0.0
9. Taylor expanded around 0 to get
   \[\color{red}{\left(100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_*}{i}\right)} \cdot n \leadsto \color{blue}{\left(100 \cdot \frac{(i * \left(\frac{1}{2} \cdot i\right) + i)_*}{i}\right)} \cdot n\]
   0.0

if 3.418504310435436e-09 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   50.9
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
   42.1
3. Taylor expanded around inf to get
   \[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
   42.1
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
   42.6
5. Applied taylor to get
   \[\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}\]
   0.3
6. Taylor expanded around inf to get
   \[\color{red}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}} \leadsto \color{blue}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}}\]
   0.3
7. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\left(\left(-\log n\right) - \left(-\log i\right)\right) \cdot n} - 1)^*\]
   0.3

---

8. Applied final simplification