- Started with
\[\frac{a \cdot c + b \cdot d}{{c}^2 + {d}^2}\]
10.3
- Using strategy
rm 10.3
- Applied add-sqr-sqrt to get
\[\frac{a \cdot c + b \cdot d}{{c}^2 + \color{red}{{d}^2}} \leadsto \frac{a \cdot c + b \cdot d}{{c}^2 + \color{blue}{{\left(\sqrt{{d}^2}\right)}^2}}\]
10.3
- Applied simplify to get
\[\frac{a \cdot c + b \cdot d}{{c}^2 + {\color{red}{\left(\sqrt{{d}^2}\right)}}^2} \leadsto \frac{a \cdot c + b \cdot d}{{c}^2 + {\color{blue}{\left(\left|d\right|\right)}}^2}\]
6.4
- Using strategy
rm 6.4
- Applied add-cube-cbrt to get
\[\color{red}{\frac{a \cdot c + b \cdot d}{{c}^2 + {\left(\left|d\right|\right)}^2}} \leadsto \color{blue}{{\left(\sqrt[3]{\frac{a \cdot c + b \cdot d}{{c}^2 + {\left(\left|d\right|\right)}^2}}\right)}^3}\]
6.7
- Using strategy
rm 6.7
- Applied add-cube-cbrt to get
\[{\color{red}{\left(\sqrt[3]{\frac{a \cdot c + b \cdot d}{{c}^2 + {\left(\left|d\right|\right)}^2}}\right)}}^3 \leadsto {\color{blue}{\left({\left(\sqrt[3]{\sqrt[3]{\frac{a \cdot c + b \cdot d}{{c}^2 + {\left(\left|d\right|\right)}^2}}}\right)}^3\right)}}^3\]
7.2
- Applied taylor to get
\[{\left({\left(\sqrt[3]{\sqrt[3]{\frac{a \cdot c + b \cdot d}{{c}^2 + {\left(\left|d\right|\right)}^2}}}\right)}^3\right)}^3 \leadsto {\left({\left(\sqrt[3]{\sqrt[3]{\frac{c \cdot a}{{\left(\left|d\right|\right)}^2} + \frac{b \cdot d}{{\left(\left|d\right|\right)}^2}}}\right)}^3\right)}^3\]
6.5
- Taylor expanded around 0 to get
\[{\left({\left(\sqrt[3]{\sqrt[3]{\color{red}{\frac{c \cdot a}{{\left(\left|d\right|\right)}^2} + \frac{b \cdot d}{{\left(\left|d\right|\right)}^2}}}}\right)}^3\right)}^3 \leadsto {\left({\left(\sqrt[3]{\sqrt[3]{\color{blue}{\frac{c \cdot a}{{\left(\left|d\right|\right)}^2} + \frac{b \cdot d}{{\left(\left|d\right|\right)}^2}}}}\right)}^3\right)}^3\]
6.5
- Applied simplify to get
\[{\left({\left(\sqrt[3]{\sqrt[3]{\frac{c \cdot a}{{\left(\left|d\right|\right)}^2} + \frac{b \cdot d}{{\left(\left|d\right|\right)}^2}}}\right)}^3\right)}^3 \leadsto \frac{b}{\left|d\right|} \cdot \frac{d}{\left|d\right|} + \frac{a}{\left|d\right|} \cdot \frac{c}{\left|d\right|}\]
0
- Applied final simplification