if i < -21048153773225.633 or 15879525.552212397 < i < 5.825932973647131e+144

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   27.5
2. Using strategy rm
   27.5
3. Applied add-log-exp to get
   \[100 \cdot \frac{\color{red}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\log \left(e^{{\left(1 + \frac{i}{n}\right)}^{n} - 1}\right)}}{\frac{i}{n}}\]
   27.5

if -21048153773225.633 < i < 15879525.552212397

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   60.7
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
   59.8
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
   59.8
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\frac{i}{n}}}\]
   16.3
5. Applied taylor to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\frac{i}{n}} \leadsto 100 \cdot n + 50 \cdot \left(n \cdot i\right)\]
   2.3
6. Taylor expanded around 0 to get
   \[\color{red}{100 \cdot n + 50 \cdot \left(n \cdot i\right)} \leadsto \color{blue}{100 \cdot n + 50 \cdot \left(n \cdot i\right)}\]
   2.3
7. Applied simplify to get
   \[\color{red}{100 \cdot n + 50 \cdot \left(n \cdot i\right)} \leadsto \color{blue}{\left(i \cdot 50 + 100\right) \cdot n}\]
   2.3
8. Using strategy rm
   2.3
9. Applied add-exp-log to get
   \[\color{red}{\left(i \cdot 50 + 100\right)} \cdot n \leadsto \color{blue}{e^{\log \left(i \cdot 50 + 100\right)}} \cdot n\]
   4.0
10. Applied taylor to get
    \[e^{\log \left(i \cdot 50 + 100\right)} \cdot n \leadsto e^{\left(\log 100 + \frac{1}{2} \cdot i\right) - \frac{1}{8} \cdot {i}^2} \cdot n\]
    1.8
11. Taylor expanded around 0 to get
    \[e^{\color{red}{\left(\log 100 + \frac{1}{2} \cdot i\right) - \frac{1}{8} \cdot {i}^2}} \cdot n \leadsto e^{\color{blue}{\left(\log 100 + \frac{1}{2} \cdot i\right) - \frac{1}{8} \cdot {i}^2}} \cdot n\]
    1.8
12. Applied simplify to get
    \[e^{\left(\log 100 + \frac{1}{2} \cdot i\right) - \frac{1}{8} \cdot {i}^2} \cdot n \leadsto \frac{e^{\frac{1}{2} \cdot i} \cdot \left(100 \cdot n\right)}{{\left(e^{\frac{1}{8}}\right)}^{\left(i \cdot i\right)}}\]
    0.5

---

13. Applied final simplification

if 5.825932973647131e+144 < i < 2.336800599734348e+283

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   50.9
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
   62.1
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
   62.1
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\frac{i}{n}}}\]
   42.8
5. Using strategy rm
   42.8
6. Applied add-cube-cbrt to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{red}{\frac{i}{n}}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{blue}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}}\]
   42.8
7. Applied add-cube-cbrt to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{red}{i \cdot 100}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{blue}{{\left(\sqrt[3]{i \cdot 100}\right)}^3}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}\]
   42.8
8. Applied cube-undiv to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \color{red}{\frac{{\left(\sqrt[3]{i \cdot 100}\right)}^3}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \color{blue}{{\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3}\]
   42.8
9. Applied taylor to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{-100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
   21.3
10. Taylor expanded around -inf to get
    \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{red}{\sqrt[3]{\frac{-100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{blue}{\sqrt[3]{\frac{-100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
    21.3
11. Applied simplify to get
    \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{-100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \frac{\frac{-100}{i}}{\frac{i}{n}} \cdot \left(i \cdot \frac{1}{2} + 1\right)\]
    20.9

---

12. Applied final simplification

if 2.336800599734348e+283 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   30.9
2. Using strategy rm
   30.9
3. Applied associate-/r/ to get
   \[100 \cdot \color{red}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)}\]
   30.9
4. Applied associate-*r* to get
   \[\color{red}{100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \leadsto \color{blue}{\left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}\right) \cdot n}\]
   30.9