- Started with
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z \cdot \sqrt{t + a}}{t} - \left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)\right)}}\]
8.5
- Using strategy
rm 8.5
- Applied associate-/l* to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\color{red}{\frac{z \cdot \sqrt{t + a}}{t}} - \left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \left(\color{blue}{\frac{z}{\frac{t}{\sqrt{t + a}}}} - \left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)\right)}}\]
6.4
- Using strategy
rm 6.4
- Applied flip-- to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z}{\frac{t}{\sqrt{t + a}}} - \left(b - c\right) \cdot \color{red}{\left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z}{\frac{t}{\sqrt{t + a}}} - \left(b - c\right) \cdot \color{blue}{\frac{{\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2}{\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}}}\right)}}\]
16.2
- Applied associate-*r/ to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z}{\frac{t}{\sqrt{t + a}}} - \color{red}{\left(b - c\right) \cdot \frac{{\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2}{\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}}}\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z}{\frac{t}{\sqrt{t + a}}} - \color{blue}{\frac{\left(b - c\right) \cdot \left({\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2\right)}{\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}}}\right)}}\]
16.7
- Applied frac-sub to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \color{red}{\left(\frac{z}{\frac{t}{\sqrt{t + a}}} - \frac{\left(b - c\right) \cdot \left({\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2\right)}{\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}}\right)}}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \color{blue}{\frac{z \cdot \left(\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}\right) - \frac{t}{\sqrt{t + a}} \cdot \left(\left(b - c\right) \cdot \left({\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2\right)\right)}{\frac{t}{\sqrt{t + a}} \cdot \left(\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}\right)}}}}\]
21.7
- Applied simplify to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \frac{\color{red}{z \cdot \left(\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}\right) - \frac{t}{\sqrt{t + a}} \cdot \left(\left(b - c\right) \cdot \left({\left(a + \frac{5.0}{6.0}\right)}^2 - {\left(\frac{2.0}{t \cdot 3.0}\right)}^2\right)\right)}}{\frac{t}{\sqrt{t + a}} \cdot \left(\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}\right)}}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \frac{\color{blue}{\left(\left(\frac{5.0}{6.0} + a\right) + \frac{\frac{2.0}{t}}{3.0}\right) \cdot \left(z - \frac{\left(b - c\right) \cdot t}{\sqrt{t + a}} \cdot \left(\left(\frac{5.0}{6.0} + a\right) - \frac{\frac{2.0}{t}}{3.0}\right)\right)}}{\frac{t}{\sqrt{t + a}} \cdot \left(\left(a + \frac{5.0}{6.0}\right) + \frac{2.0}{t \cdot 3.0}\right)}}}\]
2.2