if i < -1.0688294f-18

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   15.6
2. Using strategy rm
   15.6
3. Applied add-exp-log to get
   \[100 \cdot \frac{{\color{red}{\left(1 + \frac{i}{n}\right)}}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{{\color{blue}{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}}^{n} - 1}{\frac{i}{n}}\]
   15.6
4. Applied pow-exp to get
   \[100 \cdot \frac{\color{red}{{\left(e^{\log \left(1 + \frac{i}{n}\right)}\right)}^{n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}}\]
   15.6
5. Applied simplify to get
   \[100 \cdot \frac{e^{\color{red}{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\color{blue}{\log_* (1 + \frac{i}{n}) \cdot n}} - 1}{\frac{i}{n}}\]
   9.1
6. Applied taylor to get
   \[100 \cdot \frac{e^{\log_* (1 + \frac{i}{n}) \cdot n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{n \cdot \log_* (1 + \frac{i}{n})} - 1}{\frac{i}{n}}\]
   9.1
7. Taylor expanded around 0 to get
   \[100 \cdot \frac{e^{\color{red}{n \cdot \log_* (1 + \frac{i}{n})}} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\color{blue}{n \cdot \log_* (1 + \frac{i}{n})}} - 1}{\frac{i}{n}}\]
   9.1
8. Applied simplify to get
   \[100 \cdot \frac{e^{n \cdot \log_* (1 + \frac{i}{n})} - 1}{\frac{i}{n}} \leadsto \frac{(e^{n \cdot \log_* (1 + \frac{i}{n})} - 1)^*}{\frac{\frac{i}{n}}{100}}\]
   1.3

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9. Applied final simplification

if -1.0688294f-18 < i < 0.8279971f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   29.6
2. Using strategy rm
   29.6
3. Applied associate-/r/ to get
   \[100 \cdot \color{red}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)}\]
   29.9
4. Applied taylor to get
   \[100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right) \leadsto 100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)\]
   0.0
5. Taylor expanded around 0 to get
   \[\color{red}{100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)} \leadsto \color{blue}{100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)}\]
   0.0
6. Applied simplify to get
   \[100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right) \leadsto (\left(50 \cdot n\right) * i + \left((\left(i \cdot i\right) * \left(\frac{50}{3} \cdot n\right) + \left(n \cdot 100\right))_*\right))_*\]
   0.0

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7. Applied final simplification

if 0.8279971f0 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   24.0
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}\]
   20.4
3. Taylor expanded around inf to get
   \[100 \cdot \frac{\color{red}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{e^{\frac{\log n - \log i}{n}} - 1}}{\frac{i}{n}}\]
   20.4
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{e^{\frac{\log n - \log i}{n}} - 1}{\frac{i}{n}}} \leadsto \color{blue}{\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}}}\]
   21.3
5. Applied taylor to get
   \[\frac{(e^{\frac{\log n - \log i}{n}} - 1)^*}{\frac{\frac{i}{100}}{n}} \leadsto 100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}\]
   0.2
6. Taylor expanded around inf to get
   \[\color{red}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}} \leadsto \color{blue}{100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i}}\]
   0.2
7. Applied simplify to get
   \[100 \cdot \frac{n \cdot (e^{n \cdot \left(\log \left(\frac{1}{n}\right) - \log \left(\frac{1}{i}\right)\right)} - 1)^*}{i} \leadsto \frac{n \cdot 100}{i} \cdot (e^{\left(\left(-\log n\right) - \left(-\log i\right)\right) \cdot n} - 1)^*\]
   1.2

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8. Applied final simplification