- Started with
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z \cdot \sqrt{t + a}}{t} - \left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)\right)}}\]
0.0
- Using strategy
rm 0.0
- Applied add-log-exp to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z \cdot \sqrt{t + a}}{t} - \color{red}{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \left(\frac{z \cdot \sqrt{t + a}}{t} - \color{blue}{\log \left(e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)}\right)}}\]
2.6
- Applied add-log-exp to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \left(\color{red}{\frac{z \cdot \sqrt{t + a}}{t}} - \log \left(e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \left(\color{blue}{\log \left(e^{\frac{z \cdot \sqrt{t + a}}{t}}\right)} - \log \left(e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)\right)}}\]
12.5
- Applied diff-log to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \color{red}{\left(\log \left(e^{\frac{z \cdot \sqrt{t + a}}{t}}\right) - \log \left(e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}\right)\right)}}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \color{blue}{\log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}}\right)}}}\]
12.5
- Applied taylor to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{2.0}{t \cdot 3.0}\right)}}\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{0.6666666666666666}{t}\right)}}\right)}}\]
12.5
- Taylor expanded around 0 to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \color{red}{\frac{0.6666666666666666}{t}}\right)}}\right)}} \leadsto \frac{x}{x + y \cdot e^{2.0 \cdot \log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \color{blue}{\frac{0.6666666666666666}{t}}\right)}}\right)}}\]
12.5
- Applied simplify to get
\[\frac{x}{x + y \cdot e^{2.0 \cdot \log \left(\frac{e^{\frac{z \cdot \sqrt{t + a}}{t}}}{e^{\left(b - c\right) \cdot \left(\left(a + \frac{5.0}{6.0}\right) - \frac{0.6666666666666666}{t}\right)}}\right)}} \leadsto \frac{x}{{\left(e^{2.0}\right)}^{\left(\frac{\sqrt{a + t}}{\frac{t}{z}} - \left(\frac{5.0}{6.0} + \left(a - \frac{0.6666666666666666}{t}\right)\right) \cdot \left(b - c\right)\right)} \cdot y + x}\]
0.4
- Applied final simplification