if i < -0.97743076f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   9.8
2. Using strategy rm
   9.8
3. Applied flip3-- to get
   \[100 \cdot \frac{\color{red}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\frac{{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^{3} - {1}^{3}}{{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^2 + \left({1}^2 + {\left(1 + \frac{i}{n}\right)}^{n} \cdot 1\right)}}}{\frac{i}{n}}\]
   9.8
4. Applied associate-/l/ to get
   \[100 \cdot \color{red}{\frac{\frac{{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^{3} - {1}^{3}}{{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^2 + \left({1}^2 + {\left(1 + \frac{i}{n}\right)}^{n} \cdot 1\right)}}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{\frac{{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^{3} - {1}^{3}}{\frac{i}{n} \cdot \left({\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}^2 + \left({1}^2 + {\left(1 + \frac{i}{n}\right)}^{n} \cdot 1\right)\right)}}\]
   9.8

if -0.97743076f0 < i < 0.009737393f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   29.6
2. Using strategy rm
   29.6
3. Applied add-exp-log to get
   \[\color{red}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto \color{blue}{e^{\log \left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\right)}}\]
   29.7
4. Applied taylor to get
   \[e^{\log \left(100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\right)} \leadsto e^{\frac{1}{24} \cdot {i}^2 + \left(\log n + \left(\log 100 + \frac{1}{2} \cdot i\right)\right)}\]
   17.2
5. Taylor expanded around 0 to get
   \[e^{\color{red}{\frac{1}{24} \cdot {i}^2 + \left(\log n + \left(\log 100 + \frac{1}{2} \cdot i\right)\right)}} \leadsto e^{\color{blue}{\frac{1}{24} \cdot {i}^2 + \left(\log n + \left(\log 100 + \frac{1}{2} \cdot i\right)\right)}}\]
   17.2
6. Applied simplify to get
   \[e^{\frac{1}{24} \cdot {i}^2 + \left(\log n + \left(\log 100 + \frac{1}{2} \cdot i\right)\right)} \leadsto e^{\left(\log n + \left(i \cdot i\right) \cdot \frac{1}{24}\right) + \left(\frac{1}{2} \cdot i + \log 100\right)}\]
   17.2

---

7. Applied final simplification
8. Applied simplify to get
   \[\color{red}{e^{\left(\log n + \left(i \cdot i\right) \cdot \frac{1}{24}\right) + \left(\frac{1}{2} \cdot i + \log 100\right)}} \leadsto \color{blue}{\left(100 \cdot n\right) \cdot {\left(e^{i}\right)}^{\left(\frac{1}{24} \cdot i + \frac{1}{2}\right)}}\]
   0.1

if 0.009737393f0 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   16.6
2. Using strategy rm
   16.6
3. Applied associate-/r/ to get
   \[100 \cdot \color{red}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)}\]
   16.5