\(\frac{\log \left({\left({\left(e^{x}\right)}^{\left({z}^{y}\right)}\right)}^{\left(\frac{{a}^{\left(t - 1.0\right)}}{e^{b}}\right)}\right)}{y}\)
- Started with
\[\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}\]
47.7
- Applied simplify to get
\[\color{red}{\frac{x \cdot e^{\left(y \cdot \log z + \left(t - 1.0\right) \cdot \log a\right) - b}}{y}} \leadsto \color{blue}{\left(\frac{x}{y} \cdot {z}^{y}\right) \cdot \frac{{a}^{\left(t - 1.0\right)}}{e^{b}}}\]
35.8
- Using strategy
rm 35.8
- Applied associate-*l/ to get
\[\color{red}{\left(\frac{x}{y} \cdot {z}^{y}\right)} \cdot \frac{{a}^{\left(t - 1.0\right)}}{e^{b}} \leadsto \color{blue}{\frac{x \cdot {z}^{y}}{y}} \cdot \frac{{a}^{\left(t - 1.0\right)}}{e^{b}}\]
35.8
- Applied associate-*l/ to get
\[\color{red}{\frac{x \cdot {z}^{y}}{y} \cdot \frac{{a}^{\left(t - 1.0\right)}}{e^{b}}} \leadsto \color{blue}{\frac{\left(x \cdot {z}^{y}\right) \cdot \frac{{a}^{\left(t - 1.0\right)}}{e^{b}}}{y}}\]
33.8
- Using strategy
rm 33.8
- Applied pow-to-exp to get
\[\frac{\left(x \cdot {z}^{y}\right) \cdot \frac{\color{red}{{a}^{\left(t - 1.0\right)}}}{e^{b}}}{y} \leadsto \frac{\left(x \cdot {z}^{y}\right) \cdot \frac{\color{blue}{e^{\log a \cdot \left(t - 1.0\right)}}}{e^{b}}}{y}\]
46.5
- Applied div-exp to get
\[\frac{\left(x \cdot {z}^{y}\right) \cdot \color{red}{\frac{e^{\log a \cdot \left(t - 1.0\right)}}{e^{b}}}}{y} \leadsto \frac{\left(x \cdot {z}^{y}\right) \cdot \color{blue}{e^{\log a \cdot \left(t - 1.0\right) - b}}}{y}\]
45.4
- Using strategy
rm 45.4
- Applied add-log-exp to get
\[\frac{\color{red}{\left(x \cdot {z}^{y}\right) \cdot e^{\log a \cdot \left(t - 1.0\right) - b}}}{y} \leadsto \frac{\color{blue}{\log \left(e^{\left(x \cdot {z}^{y}\right) \cdot e^{\log a \cdot \left(t - 1.0\right) - b}}\right)}}{y}\]
46.4
- Applied simplify to get
\[\frac{\log \color{red}{\left(e^{\left(x \cdot {z}^{y}\right) \cdot e^{\log a \cdot \left(t - 1.0\right) - b}}\right)}}{y} \leadsto \frac{\log \color{blue}{\left({\left({\left(e^{x}\right)}^{\left({z}^{y}\right)}\right)}^{\left(\frac{{a}^{\left(t - 1.0\right)}}{e^{b}}\right)}\right)}}{y}\]
1.6