\(\frac{{\left(\frac{\sqrt[3]{{\left(\sin x\right)}^2}}{\sqrt[3]{1 + \cos x}}\right)}^3}{{x}^2}\)
- Started with
\[\frac{1 - \cos x}{{x}^2}\]
14.4
- Using strategy
rm 14.4
- Applied flip-- to get
\[\frac{\color{red}{1 - \cos x}}{{x}^2} \leadsto \frac{\color{blue}{\frac{{1}^2 - {\left(\cos x\right)}^2}{1 + \cos x}}}{{x}^2}\]
14.4
- Applied simplify to get
\[\frac{\frac{\color{red}{{1}^2 - {\left(\cos x\right)}^2}}{1 + \cos x}}{{x}^2} \leadsto \frac{\frac{\color{blue}{{\left(\sin x\right)}^2}}{1 + \cos x}}{{x}^2}\]
7.2
- Using strategy
rm 7.2
- Applied add-cube-cbrt to get
\[\frac{\frac{{\left(\sin x\right)}^2}{\color{red}{1 + \cos x}}}{{x}^2} \leadsto \frac{\frac{{\left(\sin x\right)}^2}{\color{blue}{{\left(\sqrt[3]{1 + \cos x}\right)}^3}}}{{x}^2}\]
7.5
- Applied add-cube-cbrt to get
\[\frac{\frac{\color{red}{{\left(\sin x\right)}^2}}{{\left(\sqrt[3]{1 + \cos x}\right)}^3}}{{x}^2} \leadsto \frac{\frac{\color{blue}{{\left(\sqrt[3]{{\left(\sin x\right)}^2}\right)}^3}}{{\left(\sqrt[3]{1 + \cos x}\right)}^3}}{{x}^2}\]
7.1
- Applied cube-undiv to get
\[\frac{\color{red}{\frac{{\left(\sqrt[3]{{\left(\sin x\right)}^2}\right)}^3}{{\left(\sqrt[3]{1 + \cos x}\right)}^3}}}{{x}^2} \leadsto \frac{\color{blue}{{\left(\frac{\sqrt[3]{{\left(\sin x\right)}^2}}{\sqrt[3]{1 + \cos x}}\right)}^3}}{{x}^2}\]
7.1