if i < -14.466003f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   9.5
2. Using strategy rm
   9.5
3. Applied add-cube-cbrt to get
   \[100 \cdot \color{red}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \leadsto 100 \cdot \color{blue}{{\left(\sqrt[3]{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}}\right)}^3}\]
   9.7

if -14.466003f0 < i < 9260.558f0

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   29.6
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}{\frac{i}{n}}\]
   5.3
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}}{\frac{i}{n}}\]
   5.3
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\frac{1}{2} \cdot {i}^2 + \left(i + \frac{1}{6} \cdot {i}^{3}\right)}{\frac{i}{n}}} \leadsto \color{blue}{\frac{100}{\frac{i}{n}} \cdot \left(i + \left(i \cdot i\right) \cdot \left(\frac{1}{6} \cdot i + \frac{1}{2}\right)\right)}\]
   7.4
5. Applied taylor to get
   \[\frac{100}{\frac{i}{n}} \cdot \left(i + \left(i \cdot i\right) \cdot \left(\frac{1}{6} \cdot i + \frac{1}{2}\right)\right) \leadsto 100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)\]
   0.1
6. Taylor expanded around 0 to get
   \[\color{red}{100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)} \leadsto \color{blue}{100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right)}\]
   0.1
7. Applied simplify to get
   \[100 \cdot n + \left(\frac{50}{3} \cdot \left(n \cdot {i}^2\right) + 50 \cdot \left(n \cdot i\right)\right) \leadsto 50 \cdot \left(n \cdot i\right) + \left(n \cdot 100 + \left(i \cdot i\right) \cdot \left(\frac{50}{3} \cdot n\right)\right)\]
   0.1

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8. Applied final simplification
9. Applied simplify to get
   \[\color{red}{50 \cdot \left(n \cdot i\right) + \left(n \cdot 100 + \left(i \cdot i\right) \cdot \left(\frac{50}{3} \cdot n\right)\right)} \leadsto \color{blue}{\left(n \cdot i\right) \cdot \left(\frac{50}{3} \cdot i + 50\right) + 100 \cdot n}\]
   0.1

if 9260.558f0 < i

1. Started with
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\]
   26.1
2. Applied taylor to get
   \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}\]
   29.5
3. Taylor expanded around 0 to get
   \[100 \cdot \frac{\color{red}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}} \leadsto 100 \cdot \frac{\color{blue}{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right)} - 1}{\frac{i}{n}}\]
   29.5
4. Applied simplify to get
   \[\color{red}{100 \cdot \frac{\left(\frac{1}{2} \cdot {i}^2 + \left(1 + i\right)\right) - 1}{\frac{i}{n}}} \leadsto \color{blue}{\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\frac{i}{n}}}\]
   24.7
5. Using strategy rm
   24.7
6. Applied add-cube-cbrt to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{red}{\frac{i}{n}}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{i \cdot 100}{\color{blue}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}}\]
   24.7
7. Applied add-cube-cbrt to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{red}{i \cdot 100}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \frac{\color{blue}{{\left(\sqrt[3]{i \cdot 100}\right)}^3}}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}\]
   24.7
8. Applied cube-undiv to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot \color{red}{\frac{{\left(\sqrt[3]{i \cdot 100}\right)}^3}{{\left(\sqrt[3]{\frac{i}{n}}\right)}^3}} \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot \color{blue}{{\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3}\]
   24.7
9. Applied taylor to get
   \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{i \cdot 100}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{-100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
   2.1
10. Taylor expanded around -inf to get
    \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{red}{\sqrt[3]{\frac{-100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\color{blue}{\sqrt[3]{\frac{-100}{i}}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3\]
    2.1
11. Applied simplify to get
    \[\left(\frac{1}{2} \cdot i + 1\right) \cdot {\left(\frac{\sqrt[3]{\frac{-100}{i}}}{\sqrt[3]{\frac{i}{n}}}\right)}^3 \leadsto \frac{\frac{-100}{i}}{\frac{i}{n}} \cdot \left(i \cdot \frac{1}{2} + 1\right)\]
    7.4

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12. Applied final simplification