if x < -0.059066683f0 or 1.2336446f0 < x

1. Started with
   \[\left(\frac{1}{x + 1} - \frac{2}{x}\right) + \frac{1}{x - 1}\]
   9.1
2. Applied taylor to get
   \[\left(\frac{1}{x + 1} - \frac{2}{x}\right) + \frac{1}{x - 1} \leadsto 2 \cdot \frac{1}{{x}^{5}} + \left(2 \cdot \frac{1}{{x}^{7}} + 2 \cdot \frac{1}{{x}^{3}}\right)\]
   0.8
3. Taylor expanded around inf to get
   \[\color{red}{2 \cdot \frac{1}{{x}^{5}} + \left(2 \cdot \frac{1}{{x}^{7}} + 2 \cdot \frac{1}{{x}^{3}}\right)} \leadsto \color{blue}{2 \cdot \frac{1}{{x}^{5}} + \left(2 \cdot \frac{1}{{x}^{7}} + 2 \cdot \frac{1}{{x}^{3}}\right)}\]
   0.8
4. Applied simplify to get
   \[\color{red}{2 \cdot \frac{1}{{x}^{5}} + \left(2 \cdot \frac{1}{{x}^{7}} + 2 \cdot \frac{1}{{x}^{3}}\right)} \leadsto \color{blue}{\left(\frac{2}{{x}^{5}} + \frac{2}{{x}^{7}}\right) + \frac{2}{{x}^3}}\]
   0.8

if -0.059066683f0 < x < 1.2336446f0

1. Started with
   \[\left(\frac{1}{x + 1} - \frac{2}{x}\right) + \frac{1}{x - 1}\]
   0.3
2. Applied taylor to get
   \[\left(\frac{1}{x + 1} - \frac{2}{x}\right) + \frac{1}{x - 1} \leadsto -\left(2 \cdot {x}^{3} + \left(2 \cdot \frac{1}{x} + 2 \cdot x\right)\right)\]
   0.0
3. Taylor expanded around 0 to get
   \[\color{red}{-\left(2 \cdot {x}^{3} + \left(2 \cdot \frac{1}{x} + 2 \cdot x\right)\right)} \leadsto \color{blue}{-\left(2 \cdot {x}^{3} + \left(2 \cdot \frac{1}{x} + 2 \cdot x\right)\right)}\]
   0.0
4. Applied simplify to get
   \[\color{red}{-\left(2 \cdot {x}^{3} + \left(2 \cdot \frac{1}{x} + 2 \cdot x\right)\right)} \leadsto \color{blue}{\left(-2\right) \cdot (\left((x * x + 1)_*\right) * x + \left(\frac{1}{x}\right))_*}\]
   0.0